8x^2-48x=104

Solution for 8x^2-48x=104 equation:

8x^2-48x=104

We move all terms to the left:

8x^2-48x-(104)=0

a = 8; b = -48; c = -104;
Δ = b2-4ac
Δ = -482-4·8·(-104)
Δ = 5632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5632}=\sqrt{256*22}=\sqrt{256}*\sqrt{22}=16\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-16\sqrt{22}}{2*8}=\frac{48-16\sqrt{22}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+16\sqrt{22}}{2*8}=\frac{48+16\sqrt{22}}{16}
$